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Ratios in a right triangle

uncharted Uncharted Not practised yet · 2 questions

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$\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}$, $\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}$, $\tan\theta = \frac{\text{opposite}}{\text{adjacent}}$. A 3–4–5 triangle is right-angled.
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